2x^2+9x-180=0

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Solution for 2x^2+9x-180=0 equation:



2x^2+9x-180=0
a = 2; b = 9; c = -180;
Δ = b2-4ac
Δ = 92-4·2·(-180)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-39}{2*2}=\frac{-48}{4} =-12 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+39}{2*2}=\frac{30}{4} =7+1/2 $

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